For the following circuit, i (t) = 0.01 cos (1000t)A. Find and draw the Norton e
ID: 1835745 • Letter: F
Question
For the following circuit, i (t) = 0.01 cos (1000t)A. Find and draw the Norton equivalent circuit.Explanation / Answer
The capacitive reactance is given by Xc=1/wC where w is angular frequency and given w=1000 =>Xc=1/(1000x0.5x10^-6)=2000ohms the inductive reactance is given by X(L)=wL=200ohms now the total impedence across the open terminals is given by Z=[R || jX(L)] || -jXc =>Z=38.46+j192.31ohms the voltage across the open terminals is given by Vth=(-j2000)Ic(t) Ic(t)=0.01cos(1000t)x(0.001-j0.005)/(0.001-j0.005-j2000) Ic(t)=(2.5x10^-8+j5x10^-9)cos(1000t) =>Vth=10^(-5)-j5x10^(-5) thevenins circuit is constructed by Vth in series with Z to find nortons circuit, the current passing through the open terminal when its shorted is completely Is(t) now norton's circuit is constructed by current source's current equal to Is(t) with a parallel impedence of Z.