For the following circuit, you ultimately want to measure the power dissipation

Question

For the following circuit, you ultimately want to measure the power dissipation of the 6.0 Ohm resistor: First, redraw the diagram on the page you are turning in. Define the directions of the currents arriving at the top junction by stating the direction of the current is at points a, b, and c (i.e. up, down, left, or right) Physically draw the directions of these currents on the diagram. Write an equation in the space below for the Kirchhoff Junction Rule for the current directions arriving at the top junction as chosen in part a). Choose two Kirchhoff loops that include the 6.0 Ohm resistor. Physically draw these two loops on the diagram. Write out a simple equation for each circuit element in your two Kirchhoff loops (note you should have two equations). Clearly denote for each term whether it is a rise ( + ) in voltage or a drop ( - ) in voltage for your Kirchhoff loops.

Explanation / Answer

Assume node of poit a is Va

Now using KCL rule at node a --

(Va-8)/4 + (Va-4)/2 + (Va-0)/6 =0

Va*(0.91667) = 4

Va =4.37V

current in 6ohm resistor -

I =(Va-0)/6

I = 4.37/60 =0.72727 A

Power = Va*I = (4.37*0.72727) = 3.18 W

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