Please solve all three parts m1 = 190 lb m2 = 205 lb V1/B = 4 ft/s right arrow V
ID: 1858365 • Letter: P
Question
Please solve all three parts
m1 = 190 lb m2 = 205 lb V1/B = 4 ft/s right arrow V2/B = 3 ft/s left arrow mB = 400 lb Question: Mass I goes to the center of the boat at a velocity of 4 ft/s, while mass z stays at its initial position, locate the new center of mass of the boat. Secondly, while mass l is positioned at the center of the boat, mass z goes to the center of the boats at the velocity of 3 ft/s, locate the new center of mass of the boat. Lastly, while M1 M2 are at the center of the boat, find the new center of the mass of the boat.Explanation / Answer
1) 1 walks with a speed 4ft/s w.r.t. boat for a distance 10 in
=> t = 10/4*12 = 0.208s
COM moves distance d in opposite direction with speed Vcm for t time:
Vcm = 190*4 /(190+205+400) = 0.956 ft/s
=> d = 2.39 in
New COM = Old - 2.39 = (400*10+205*20)/(190+205+400) - 2.39 = 7.8 in
2) t = 10/(3*12) = 0.278 s
Vcm = - 3*205/(795) = - 0.774 ft/s
d = 2.58
New COM = 7.8 + 2.58 = 10.38
3)New COM remains at 10.38 in
All COM are measured keeping the initial position of 1 as origin.