Here is the homework I need help with! Toluene (C7HS) is frequently used as a so
ID: 1859057 • Letter: H
Question
Here is the homework I need help with!
Toluene (C7HS) is frequently used as a solvent or thinner for oil-based paints. Assess potential CPC glove materials to protect against exposure to toluene. Based on airborne exposure limits set by the Occupational Safety and Health Administration (OSHA) of the United States, the maximum allowable exposure rate to toluene is approximately 8 g/h. The diffusion coefficients and surface concentrations for toluene in several materials are as follows: Determine the breakthrough time and expo-sure rate for each of these materials. Discuss which of these materials would be appropriate for use as a CPC glove material for toluene.Explanation / Answer
PART A
Exposure rate = [(Diffusion coefficient)*(Surface concentration)*3600]*A/l
EXPOSURE RATE is proportional to [(Diffusion coefficient)*(Surface concentration)*3600]
For Same A And l we can compare the above product
To get the unit in g/h we multiplied by 3600
Break through time = 8/EXPOSURE RATE
Butyl rubber = 61*2.55*3600*(10^ -8) = 56*(10^ -4) *A/l
Break through time = 1428.57 h *l/A
Multilayer silver shield = 0.0089*7.87*3600*(10^ -8) = 2.52*(10^ -6) *A/l
Break through time = 3.18*(10^6) h *l/A
Neoprene rubber =64*3.53*3600*(10^ -8) = 8.13*(10^ -3) *A/l
Break through time = 984 h *l/A
Nitrile rubber = 15*2.68*3600*(10^ -8) = 1.45*(10^ -3) *A/l
Break through time = 5517.3 h *l/A
Poly vinyl alcohol = 1.28*0.68*3600*(10^ -8) = 3.13*(10^ -5) *A/l
Break through time = 2.56*(10^5) h *l/A
Poly vinyl chloride = 100*0.25*3600*(10^ -8) = 9*(10^ -4) *A/l
Break through time = 8888.9 h *l/A
Viton rubber = 0.73*2.61*3600*(10^ -8) = 6.86*(10^ -5) *A/l
Break through time =1.17*(10^5) h *l/A
PART B
Multilayer silver shield would be appropriate for CPC glove material for toluene as it has the maximum breakthrough time = 3.18*(10^6) h *l/A