Please Help with thermo problem An industrial process discharges 200,000 cubic f
ID: 1859601 • Letter: P
Question
Please Help with thermo problem
Explanation / Answer
1 atm = 14.7 psi
For air, gas constant R = 1716 ft-lb/slug-R
For air, Cp = 0.24 Btu/lb-R
Density of inlet combustion products = P1/(R*T1) = 14.7*12^2 / (1716*(400+260)) = 0.00187 slug/ft^3 = 0.00187*32.2 lb/ft^3
From steam properties, Inlet enthalpy of water at 40 psi and 102 F is h3 = 70.1 Btu/lb
Energy balance in generator: (2*10^5/60) *(0.00187*32.2)*0.24*(400-260) = (275/60)*(h4 - 70.1)
thus, h4 = 1541.5 Btu/lb
From steam properties at P4= 40 psi and h4 = 1541.5 Btu/lb, we get T4 = 1010 deg F
b)
From steam properties at 1 psi and quality = 93%, we get entahlpy h5 = 1030 Btu/lb
Turbine output = m*(h4 - h5)
Turbine power = 275*(1541.5 - 1030) = 140665.6 Btu/min
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