Point charges q1= 4.90 nC and q2=+ 4.90 nC are separated by distance 3.90 mm , f

Question

Point charges q1= 4.90 nC and q2=+ 4.90 nC are separated by distance 3.90 mm , forming an electric dipole.

Part A

Find the magnitude of the electric dipole moment.

Express your answer in coulomb meters to three significant figures.

Part B

What is the direction of the electric dipole moment?

Part C

The charges are in a uniform electric field whose direction makes an angle 36.7 with the line connecting the charges. What is the magnitude of this field if the torque exerted on the dipole has magnitude 8.00×109 Nm ?

Express your answer in newtons per coulomb to three significant figures.

Explanation / Answer

Point charges q1=- 4.90nC and q2=+ 4.90nC are separated by a distance of 3.90mm , forming an electric dipole.

A.)

The magnitude of the electric dipole moment= p =(4.90*10^-9)( 3.90*10^-3 ) =1.911*10^-11 Cm

B.)

The direction of the electric dipole moment is from q1 to q2

C.)

The charges are in a uniform electric field E whose direction makes an angle of 36.7degrees with the line

connecting the charges.

The torque exerted on the dipole = t =8.00*10^9 N.m

pEsinO = torque = t

E = t / psinO

E = 8.00*10^9/1.911*10^-11*(sin36.7)

E = 8.00*10^9/1.911*10^-11 (0.5976)

E = 700.51 N/C = 7.0*10^2 N/C

the magnitude of this field is E = 7.00*10^2 N/C

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