Constants I Periodic Table Part A A 6.70-C particle moves through a region of sp
ID: 1871940 • Letter: C
Question
Constants I Periodic Table Part A A 6.70-C particle moves through a region of space where an electric field of magnitude 1200 N/C points in the positive z direction, and a magnetic field of magnitude 1.03 T points in the positive z direction. If the net force acting on the partidle is 6.25 10-3 N in the positive z direction, find the components of the particle's velocity. Assume the particle's velocity is in the zy plane. Enter your answers numerically separated by commas. m/s Submit Request Answer Provide Feedback Next >Explanation / Answer
Q = 6.70 x 10^-6 C
E = 1200 N/C --->+x direction
B = 1.03 T ------>+z direction
Fnet = 6.25x 10^-3 N ----->+x direction
Fnet = Fe - Fb
=qE - qvB
Solve for v so v = (1/B)(E - (Fnet/q)) = 259.38 m/s
Once you get the value for velocity. You need to know which direction it's going.
You know +x direction for E, +z direction for B and +x for Fnet.
Do the right hand rule where:
your right thumb goes toward the Fnet, then your index finger points to B (z direction) Then curl your middle,ring, and pink 90 angle. This shows where v is going which is -y direction.
Answer: vx, vy,vz =
(0, - 259.38, 0) m/s