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Please any one can do this calculations and explain why I1=I2 =I3 =Itotal To ill

ID: 1874549 • Letter: P

Question

Please any one can do this calculations and explain why I1=I2 =I3 =Itotal To illustrate the aplicahon of Ohm's Law to Sne crcs d R. (1) Three resistors: Ri Color code/nominal value Measured value (ohm) % error Calculate I's using the following equations: 15005%. :550521 3.3 V-2R2 Vi hRi, and R2 Color code / nominal valueMeasured value (ohm) 1000 ± 5v, % error Show your calculations. Use the scientific notation. Ii. 12. Is, and I %error Color code /nominal value Measured value (ohm 1200± 5% -20 12 00 Series Connection Measurements in ohm: R12 . 2.55 2550 R21 . 2.20 2200,S2 Connect a battery and measure in volt; 12 V 6.3 Calculation (using measured value of R,, R:, and Ro) in ohm: R23 = R123= Questions: 11-12-13=L? Explain why

Explanation / Answer

calculation (using measured value of R1, R2,R3 ) in ohm:

R12 = R1 +R2 = 1550 +1000 = 2550 ohms

R23= R2 + R3 = 1000 +1200 = 2200 ohms

R123 = R1 +R2 + R3 = 1550 +1000+1200 = 3750 ohms

calculation of currents is as follows:

1) as V1 = I1 *R1

   2.61 = I1 *1550
   I1 = 2.61/1550 = 1.68 X 10^-3 A    (mA = MILLI AMPERES )
           = 1.68 mA
2) as V2 = I2 *R2

   1.68 = I2 *1000
   I2 = 1.68/1000 = 1.68 X 10^-3 A    (mA = MILLI AMPERES )
           = 1.68 mA
3) as V3 = I3 *R3

   2 = I3 *1200
   I3 = 2/1200 = 1.67 X 10^-3 A    (mA = MILLI AMPERES )
           = 1.67 mA
4) as V123 = I123 *R123

   6.32 = I123 *3750
   I123 =6.32/3750 = 1.68 X 10^-3 A    (mA = MILLI AMPERES )
           = 1.68 mA

I123 =   I total