Class Management Help HWE021 Begin Date: 914/2018 700:00 AM -Due Date: 9/6/2018
ID: 1876976 • Letter: C
Question
Class Management Help HWE021 Begin Date: 914/2018 700:00 AM -Due Date: 9/6/2018 7:0000 AM End Date: 12/10/2018 11 59.00 PM (11%) Problem 2: Objects A and B u teract using a force that obeys reciprocity ( the force from A onto B and the force from B on A add to zero as vectors) If the masses are mA-8 and m 30.5, and at the time t 47s the objects are at rest and the force between the two objects is IF I 16.5 33% Part (a) At a later tme of47 + 17 s, which object is moving faster? Object A Cerrect What is the magnitude of the momentum of object A at the later tree of 47 + 17 s m kg m/s. 33% Part (b) PA 5061 X Attepts Rentaln 33% Part (c) what is the magnitude of the momentum ofobjectB at the later time of47+17 s m kg m/s. Grade Sumuma Deductions Potentia sin0 cot acos0 atan acotan sinh0 cosh tan0 cotanh0 Suhmissions Attempts remair (0ge per attemp cos0 detailed view Degrees O Radans Subnut I give upl Hints: 0 for a 0% deduction. Harts retiring Feedback: 09% de deton per feedbackExplanation / Answer
(a) From Conservation of linear momentum ( treating force between A & B as internal Force)
Momentum of A + Momentum of B = 0 (at any time), therefore since mass of A is less than that of B, speed og object A will be more.
Answer: Object A
(b) Applying formula, Impilse = Force x time = change in momentum
therefore, 16.5 x 17 = momentum of A
Answer = 16.5 x 17 = 280.5 kgm/s
(c) From Conservation of linear momentum, magnitude of momentum of B will also be same as that of A
Answer = 280.5 kgm/s