Part B Find the net force EF acting on particle 3 due to the pressence of the ot
ID: 1877758 • Letter: P
Question
Part B Find the net force EF acting on particle 3 due to the pressence of the other two particles.Report you answer as a magnitude Fs and a direction 0 measured from the positive x axis. Learning Goal: To practice Problem-Solving Strategy 21.1 Coulomb's Law. Express the magnitude in newtons and the direction in degrees to three significant figures. Three charged particles are placed at each of three comers of an equilateral triangle whose sides are of length 2.8 cm. Two of the particles have a negative charge: q1--8.6 nC and g2 -17.2 nC. The remaining particle has a positive charge, qs -8.0 nC. What is the net electric force acting on particle 3 due to particle 1 and particle 2? View Available Hint(s) Submit X Incorrect; Try Again; 6 attempts remaining; no points deducted Your answer does not have the correct number of comma-separated terms.Explanation / Answer
Since equilateral triangle has each angles as 60 degree, the angle between the forces due to q1 and q2 will be 60 degree. We have assumed q1 is at top, q2 is at left q3 is at right towards x direction.
F1 = kq1q3/r^2 = 9e9*8.6e-9*8e-9/2.8e-2^2 = 0.00079 N
F2 = kq2q3/r^2 = 9e9*17.2e-9*8e-9/2.8e-2^2 = 0.00158 N we have F2 double of F1
Net force on Q3 = sigma F3 = sqrt(0.00158^2+0.00079^2 + 2*0.00079*0.00158)
= 0.00237 N
theta = arctan( (1 sin 60 degree) / (-1 cos 60 degree - 2)) = arctan(0.866/-2.5)
= 180 - 19 degree
= 161 degree
Answer : 0.00237 , 161