Parts a-g please. People Window Help 1118412/ 88702module tem_Jd 11644577 3 (Fal

Question

Parts a-g please.

People Window Help 1118412/ 88702module tem_Jd 11644577 3 (Fall 2018)Assignments HW04 HW04 t2%) Problem 18: A circuit consisting of5 resistors is shown in the graph. Their sistances are R,-17,R': 75 ,R,-89 , R4 45.Nnd R,-39Q,and te eet f the battery isc5.5 V. Suppose the internal resistance of the battery is zero. Ra Ctbeespertta.com i 14% Part (a) Express the equivalent resistance of the combination of R2.RJ,and R. 14% Part (b) Express the iotal resistance of the circus R terms of R/-R2. Ry, R., and R5 14% Part (c) Calculate the numerical value of the total musunce Rn 14% Part (d) Express be current through R, in terms ofthe emfe and the c qui valet misuse i 14% Part (e) Calculate the naeerical value of, in A 14% Part (n Express thepower Pdissipaled by R/thro gh , and R, 14% Part (g) Calculate the numerical value of the power P in w

Explanation / Answer

Check that values of Resistances taken by me are correct, as your figure was not clear. Let me know in the comments if there is any difference in any value.

A.

R2, R3 and R4 are in parallel, So their equivalent will be

1/Rp = 1/R2 + 1/R3 + 1/R4

1/Rp = (R3*R4 + R2*R4 + R2*R3)/(R2*R3*R4)

Rp = (R2*R3*R4)/(R3*R4 + R2*R4 + R2*R3)

B.

Now R1, Rp and R5 are in series, So

Req = R1 + Rp + R5

Req = R1 + [(R2*R3*R4)/(R3*R4 + R2*R4 + R2*R3)] + R5

Req = R1 + R5 + [(R2*R3*R4)/(R3*R4 + R2*R4 + R2*R3)]

C.

Using given values

Req = 17 + 39 + [(75*89*45)/(75*89 + 89*45 + 75*45)]

Req = R = 77.37 Ohm

D.

Since R1 is in series with battery, So current in R1 will be equal to total current in circuit.

i1 = ieq

Now from ohm's law

E = ieq*R

ieq = E/R

Using this

i1 = Current through R1 = E/R

E.

Numerical value will be

i1 = 5.5 V/(77.37 Ohm)

i1 = 0.0711 Amp

F.

Power is given by:

Power = Current^2*Resistance

current through R1 = I

Resistance = R1

So,

Power = I2*R1

G.

Numerical values will be

P = 0.0711^2*17

P = 0.0859 W

Please Upvote. Comment below if you have any doubt.

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