In the Atwood machine shown below, m1 = 2.00 kg and m2 = 6.30 kg. The masses of

Question

In the Atwood machine shown below, m1 = 2.00 kg and m2 = 6.30 kg. The masses of the pulley and string are negligible by comparison. The pulley turns without friction and the string does not stretch. The lighter object is released with a sharp push that sets it into motion at v 2.20 m/s downward. m1 my (a) How far will m1 descend below its initial level? Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. m (b) Find the velocity of m after 1.80 s magnitude direction Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. ms upward

Explanation / Answer

here,

m1 = 2 kg

m2 = 6.3 kg

the accelration , a = net force/effective mass

a = ( m2 - m1) * g /( m1 +m2)

a = ( 6.3 - 2) * 9.81 /( 2 + 6.3) m/s^2

a = 5.08 m/s^2

a)

the height m2 desend below , h = v^2 /2a

h = 2.2^2 /(2*5.08) m = 0.48 m

b)

at t = 1.8 s

the velocity , v = 0 + a * t

v = 0 + 5.08 * 1.8 m/s = 9.1 m/s

the direction of m2 velocity is downwards

the direction of m1 velocity is upwards

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