Constants| Periodic Table Part A In the winter sport of curling, two teams alter

Question

Constants| Periodic Table Part A In the winter sport of curling, two teams alternate sliding 20 kg stones on an icy surface in an attempt to end up with the stone closest to the center of a target painted on the ice. During one turn, a player releases a stone that travels 27.9 m before coming to rest. The friction force acting on the stone is 2.0 N. What was the speed of the stone when the player released it? Express your answer with the appropriate units. (v,),- 1 Value Units Submit Reques Answer Provide Feedback

Explanation / Answer

Using work energy theorem

Workdone by friction= change in kinetic energy

2*27.9= 0.5*20* v^2

v= 2.3622 m/s

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