Please can you draw a descriptive picture and explain how it’s done, and can you
ID: 1883499 • Letter: P
Question
Please can you draw a descriptive picture and explain how it’s done, and can you please use show what formulas are used have to present this and don’t understand rs/Leeab/AppData/Local/Microsoft/Windows/INetCache/E/NZ061 GP/Formula%20sheet%20OpenSta Equations (mostly) from OpenStax College, College Physics. OpenStax College. 21 June 2012 Download for free at http://enx.org/content/col11406/latest/. [18.3] Coulomb's Law: F,-k19i [18.11], q the only mobile charge [18.13] 1 -kla [19.1]V q the only mobile charge [19.PE] PE=kQq [19.V] V=kQ [19.4] 1 Volt-1 Joule /1 Coulomb [20.2] 1 Ampere 1 Coulomb/1 se [20.8 Ing Av [20.141 Ohm's Law: I [20.15] 10him-10= [20.17] Ohm's Law: V IR [20.18 R-pz 1 Volt 1 Ampere PE [20.23] Power: (HAT) [19.13] 1 eV-1.602176565 x 1019 J [20.26] [20.28] P=t=t [19.251 E43, unifom E-field only P=IV 1930 [19.EF] Electric Flux : ,-EAcos [19,Gauss] ,-- Infinite sheet with charge density = Q /A: [20.29] P=R [20.30] P-FR [20.34] Energy and Power: E- Pt Alternating Current: [20.38] Vlt)-Vosint2xft) 120.39] 1it)-1,sin 21ft) 22E (away from sheet) [20.39b] R-v Iit I 2 2,4 Capacitors [19.50] CV [19.51] 1 Farad 1 Coulomb 1 Volt [20.40]PV 20.41] Parallel-Plate CapacitorExplanation / Answer
As the centripital force is balanced by coulomb's attraction then
K(q1)(q2)/r^2= mrw^2
9*10^9*(2*1.6*10^-19)*1.6*10^-19/(2.66*10^-11)^2= 9.11*10^-31* (2.66*10^-11) w^2
w= 1.64*10^17 rad/s
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Commemt in case any doubt.. good luck