Here\'s yet another polar curve: Clear [x, y, r, t]; r[t_] = 5 + 3 Cos [3 t] -1.

Question

Here's yet another polar curve: Clear [x, y, r, t]; r[t_] = 5 + 3 Cos [3 t] -1.5Sin[5t]; x[t_] = r[t] Cos[t]; y[t_] = r[t] Sin[t]; tlow = 0; thigh = 2 7 pi ; original = ParametricPlot[{x[t], y[t]}, {t, tlow, thigh}, I Plotstyle rightarrow {{Blue, Thickness [0.02] }}, AspectRatio rightarrow Automatic, Axes Label rightarrow {"x", "y"}] As t advances from 0 to 2 pi , this curve plots out in the counterclockwise manner with no segment repeated. Explain why you can calculate the area inside this curve by calculating y[t]x'[t]dt: Or by calculating

Explanation / Answer

by calculating second integral

Related Questions

Navigate

• Browse (All)
• Browse H
• Subjects

---