Solve the system of equations: x-y-z=2 x+2y-2z=3 3x-2y-4z=5 Solution well, you h

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well, you have: 1- x-y-z=2 2- x+2y-2z=3 3- 3x-2y-4z=5 multiply both sides of the equation 1 by 2: x-y-z=2 ===> 2x-2y-2z=4 add this by equation 2: 2x-2y-2z=4 x+2y-2z=3 ==> 3x - 4z = 7 (*) now, multiple both sides of equation 1 by -2: x-y-z=2 ==> -2x + 2y + 2z = -4 add this by equation 3: -2x + 2y + 2z = -4 3x-2y-4z=5 ===> x - 2z = 1 great. now you have x - 2z = 1 and 3x - 4z = 7 so , multiple both sides of the first one by -2: -2x + 4z = -2 3x - 4z = 7 ===> (add them together) x = 5 3x - 4z = 7 ===(x=5)=> 15 - 4z = 7 ==> 4z = 8 ==> z=2 x-y-z= 2 ===> 5-y-2 = 2 ==> y=1

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