Correct Answer: A) 0, 0 B) F=0, Torque= 0.0809 Nm I NEED THE WORK! A rectangular
ID: 1898658 • Letter: C
Question
Correct Answer: A) 0, 0 B) F=0, Torque= 0.0809 Nm
I NEED THE WORK!
A rectangular coil of wire 22. 0 cm by 35. 0 cm and carrying a current of 1. 40 A is oriented with the plane of its loop perpendicular to a uniform 1. 50 T magnetic field, as shown in Figure 20. 66. (a) Calculate the net force and torque that the magnetic field exerts on this coil, (b) The coil is now rotated through a 30. 0 degree angle about the axis shown, the left side coming out of the plane and the right side going into the plane. Calculate the net force and torque that the magnetic field exerts on the coil. (Hint: In order to help visualize this three-dimensional problem, make a careful drawing of the coil as viewed along its axis of rotation. ) FIGURE 20. 66 Problem 37.Explanation / Answer
net force actin gon s loop is given by F = iBL sin,
where is the angle made by normal of the loop w.r.t to field.
here plane is perpendicular to field it means normal is held along or parallel to the field, therefore it makes an angle of 0 deg.
a. therefore net force F = 0, since sin 0 = 0.
torque = IABsin = 0 again since sin 0 = 0.
b. when = 30,
net force F = 1.4* 0.35*1.5* sin 30
= 0.3675 N
torque = IABsin
= 1.4* 0.35*0.22*1.5* sin 30
= 0.08085 Nm