Consider the expansion of 60.0 moles of a monatomic ideal gas along processes 1

Question

Consider the expansion of 60.0 moles of a monatomic ideal gas along processes 1 and 2 in the figure below. In process 1 the gas is heated at constant volume from an initial pressure of Pi = 95 kPa to a final pressure of Pf = 190 kPa. In process 2 the gas expands at constant pressure from an initial volume of Vi = 0.85 m3 to a final volume of Vf = 2.55 m3. (a) How much heat is added to the gas during these two processes? process 1 120 kJ process 2 810 kJ (b) How much work does the gas do during this expansion? kJ (c) What is the change in the internal energy of the gas? kJ

Explanation / Answer

b)W=PV=190*103*(2.55-0.85)=323000J=323kJ

c)W=nRT=323000

T=647.5K

U=nCvT=60*1.5*8.314*647.5=484.5kJ

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---