In the ?gure is shown the Otto cycle. Paths A and C are adiabatic (Q = 0), and p
ID: 1916625 • Letter: I
Question
In the ?gure is shown the Otto cycle. Paths A and C are adiabatic (Q = 0), and paths B and D are at constant volume (?V = 0). Consider the working substance of this engine to be an ideal gas. For each path, indicate on the chart below whether the work W done on the gas is positive (+), negative (?), or zero (0). Also indicate the sign of the net work for the entire cycle. Repeat for the heat Q put into the gas, and the change of internal energy ?Eint of the gas. Now, using your completed chart, answer the following question. Is the work done on the gas along path A positive, negative, or zero? You only get one try answering this question.
5.10. In the previous problem, is the change in internal energy of the gas along path Bpositive, negative, or zero? You only get one try answering this question.
5.11. In the previous problem, is the change in internal energy of the gas along path Cpositive, negative, or zero? You only get one try answering this question.
5.12. In the previous problem, is the heat put into the gas along path D positive, negative, orzero? You only get one try answering this question.
5.13. In the previous problem, is the net work done on the gas during the entire cycle positive,negative, or zero? You only get one try answering this question.
5.14. In the previous problem, is the net heat put into the gas during the entire cycle positive,negative, or zero? You only get one try answering this question.
Explanation / Answer
1)as V is negative in process A
work done on the gas along A is POSITIVE
2)as V is constant along B
PT so P is increasin and hence T
so internal enegy increases, POSITIVE
3)as TV(-1)= constant
and V is increasing along T decreases and hence
Internal energy decreases,NEGATIVE
4)Path D,as work done on the gas is zero as V is constant
also T is decreasing with P , so heat must be removed and hence ,NEGATIVE
5)from the figure it is clear that during entire work is done by the gas
and hence NEGATIVE
6)as internal energy is 0 and work done negative
hence heat put during entire cycle is POSITIVE
plz rate best answer first