Particle A of charge 4.00 10-4 C is at the origin, particle B of charge -5.00 10

Question

Particle A of charge 4.00 10-4 C is at the origin, particle B of charge -5.00 10-4 C is at (7.00 m, 0) and particle C of charge 2.00 10-4 C is at (0, 4.00 m). (a) What is the x-component of the electric force exerted by A on C? N (b) What is the y-component of the force exerted by A on C? Your response differs from the correct answer by more than 10%. Double check your calculations. N (c) Find the magnitude of the force exerted by B on C. N (d) Calculate the x-component of the force exerted by B on C. Your response differs from the correct answer by more than 10%. Double check your calculations. N (e) Calculate the y-component of the force exerted by B on C. The response you submitted has the wrong sign. N (f) Sum the two x-components to obtain the resultant x-component of the electric force acting on C. N (g) Repeat part (f) for the y-component. N (h) Find the magnitude and direction of the resultant electric force acting on C. magnitude N direction

Explanation / Answer

force between two charges is given F12 = Kq1q2/r^2 where K = 9*10^9 and r = distance between the charges.
apply this formula and try obtain the solution

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