Medium No. of colonies Complete medium Complete medium + ampicillin Minimal medi
ID: 193092 • Letter: M
Question
Medium No. of colonies Complete medium Complete medium + ampicillin Minimal medium (glucose as a carbon source) Minimal medium + ampicillin (an antibiotic) Minimal medium +methionine (an amino acid) Minimal medium +arginine (an amino acid) Minimal medium +methionine+ampicillin Minimal medium + arginine+ampicilin 16 15 26 12 10 contains all amino acids, vitamins, and a variety of carbon sources The table above summarizes the results of a replica-plating experiment where a mixture of 36 E. coli strains of different genotypes were tested for their ability to growth on a variety of media. Based on the data presented in the table above, how many colonies are met(+) arg(-? 2 3 4 15 16 18 20 36Explanation / Answer
A. Number of colonies that are met(+) = 26
. Number of colonies that are arg(+) = 22
. Number of colonies that are arg(-) = 36 - 22 = 14
Thus , Number of colonies that are met(+)arg(-) <= 14.
Hence from the options 11 is correct.
B.. Number of colonies that are amp(S) = 90 - 17 = 73
Number of colonies that are met(+)amp(R) = 30
Number of colonies that are met(+) = 64
Therefore, Number of colonies that are met(+)amp(S) <= 90 - 30 = 60
Similarly,
Number of colonies that are arg(+)amp(R) = 24
Number of colonies that are arg(+) = 54
Now Number of colonies that are arg(+) amp(S) <= (90 - 24) = 66 > 54(arg(+))
Thus Number of colonies that are arg(+) amp(S) <= 54
Finally Number of colonies that are met(+) arg(+) amp(S) <= 54 (as 60(met(+)amp(S)) > 54(arg(+)amp(S)))
From the options 50 is correct.
C. Number of colonies that are met(-) = 90 - 64 = 26
Number of colonies that are met(+)amp(R) = 30
Number of colonies that are amp(R) = 17
Number of colonies that are met(-)amp(R) <= 17
Number of colonies that are arg(-) = 36
Number of colonies that are arg(-)amp(R) <=17
Therefore, Number of colonies that are met(-)arg(-)amp(R) <= 17
Hence 17 is the right option.