Correct In order to interpret the chi square value, one must also determine the
ID: 193746 • Letter: C
Question
Correct In order to interpret the chi square value, one must also determine the degrees of freedom and the corresponding probability value Degrees of freedom are equal to n-1 categories into which the data are divided. For the test of a 3:1 ratio, in the case of tall vs. dwarf plants, there are two categories to consider, giving us 2-1 or 1 degree of freedom. Using the table provided, a p value between 0.3-0.5 is obtained. Because a p value of 0.05 or greater is obtained, we can fail to reject the null hypothesis, meaning that there is no significant difference between the measured values and the predicted values. If we fail to reject the null hypothesis, this means that the observed deviation can be reasonably attributed to chance and that the experimental data fit the 3:1 ratic Imagine that you attempted to recreate Mendel's work with garden peas. You began by crossing true breeding violet-flowered, tall plants with white-flowered dwarf plants After self-crossing the F1 generation, you obtain the following phenotypes in the F2 generation: 80 tall, violet flowers 36 tall, white flowers 39 dwarf, violet flowers 5 dwarf, white flowers Probability IP) Value 0.30 1.07 2.41 0.90 0.016 0.21 0.58 1.06 1.61 0.50 0.46 1.39 237 3.36 0.10 0.001 10.83 3.82 0.95 020 3.84 5.99 782 949 1.64 921 1.35 13.28 15.09 16.81 18.48 20.09 4.61 464 0.71 4.88 7.78 18.47 7.29 20.52 12.59 4.07 15.51 1.64 7.23 2.83 4.67 635 980 12.02 24.32 3.49 5.53 7.34 9.52 13.36 26.13 Part G Use a chi-square analysis to test the hypothesis that the F2 data for stem length (tall:dwarf) and flower color (violet:white) is consistent with Mendel's law of independent assortment. Calculate the chi square value Express your answer to two decimal points (example: 100.00) Submit Previous Answers Request Answer X Incorrect; Try Again; 3 attempts remainingExplanation / Answer
Answer:
Chi-Squrar value = 7.51
Degrees of freedom = n-1
n = Number of phenotypes
Degrees of freedom = 4-1 = 3
The p value between 0.1 - 0.05 is obtained. So, reject null hypothesis. It means that there is a singnificant difference between measured value and predicted value.
Phenotype Observed(O) Expected (E) O-E (O-E)2 (O-E)2/E tall, violet flowers 80 90 -10 100.00 1.11 Tall, white flowers 36 30 6 36.00 1.20 dwarf, violet flowers 39 30 9 81.00 2.70 dwarf, white flowers 5 10 -5 25.00 2.50 160 160 7.51