A convex-convex lens has radii of curvature with magnitudes of |R_1|=10cm and |R

Question

A convex-convex lens has radii of curvature with magnitudes of |R_1|=10cm and |R_2|=15cm. The lens is made of glass with index of refraction n_glass=1.5. We will employ the convention that R_1 refers to the radius of curvature of the surface through which light will enter the lens, and R_2 refers to the radius of curvature of the surface from which light will exit the lens.

What is the focal length f of this lens in air (index of refraction for air is n_air=1)?
Express your answer in centimeters to two significant figures or as a fraction.

Explanation / Answer

focal length = f

1/f = ( - 1)[1/R1 - 1/R2 ]

R1 and R2 are radius of curvatures

1/f = 0.5[1/30]

f = 60 cm

f = 0.60 * 102 cm

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