Consider these four cases: Case 1: Mass = 4.0 kg; Force 1 = 10 N; Force 2 = 2 N;
ID: 1958956 • Letter: C
Question
Consider these four cases:
Case 1: Mass = 4.0 kg; Force 1 = 10 N; Force 2 = 2 N; Force 3 = -2 N.
Case 2: Mass = 3.5 kg; Force 1 = 10 N; Force 2 = 0; Force 3 =0.
Case 3: Mass = 2.0 kg; Force 1 = 9 N; Force 2 = 3 N; Force 3 = -2 N.
Case 4: Mass = 2.0 kg; Force 1 = 5 N; Force 2 = 0; Force 3 = 0.
(b) Rank these cases by the acceleration of the block, from largest to smallest.
Please explain answers
Explanation / Answer
a) First we find the forces on each. Case 1; 10n + 2n -2n = 10 N Case 2; 10N Case 3; 10N Case 4; 5N So we have case 1 = case 2 = case 3 > case 4 B) Now we have to find the acceleration F = m*a Case 1 a = F/m = 10 N / 4 kg = 2.5 m/s2 Case 2 10/3,5 Case 3 10/2 = 5 m/s2 Case 4 5/2 = 2.5 m/s2 Case 3 > case 2 > case 4 = case 1