Consider theequilibrium? At a certain temperature theequilibrium constant for th

Question

Consider theequilibrium?

At a certain temperature theequilibrium constant for the reaction is 0.0255. What is thepartial   

pressure of NO gas at equilibriumif the initial pressure of all the gases (both reactants and

products) is 0.300 atm?

Explanation / Answer

N2   +    O2      = >      2NO initial       0.3            0.3                   0.3 change     -x               -x                  +2x equil     0.3 -x           0.3 -x            0.3 + 2x K = [NO]2 /[N2][O2] = (0.3 + 2x)2 /[(0.3-x)(0.3-x) ] = [(0.3 + 2x)/(0.3 - x)]2 = 0.0255 take square root of both sides (0.3 + 2x)/(0.3 - x) = 0.159687194~ 0.1597 0.3 + 2x = 0.3*0.1597 - 0.1597x (2 + 0.1597)*x = (0.3*0.1597 - 0.3) x = (0.3*0.1597 - 0.3) / (2 + 0.1597) = = -0.116727016 PNO = 0.3 + 2*x = 0.066545968 ~ 0.0665 atm

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