In the Atwood\'s machine, mass 1 has a weight of 50 N and mass 2 has a weight of
ID: 1959168 • Letter: I
Question
In the Atwood's machine, mass 1 has a weight of 50 N and mass 2 has a weight of 75 N. The rope and the pulley's are massless and there is no friction.A) What is the accleration of mass 1?
Answer: 1.96 m/s ^2
***B)Suppose mass 2 is removed and instead you supply a downward force of 75 N by pulling on the rope. Will the acceleration of mass 1 be greater than, equal to, or less than the accerleatiion you found in part A? Explain.
(I think the answer would be equal to, but if it's not could someone explain why?)
Explanation / Answer
A) Net force on lighter block ( m1) : T - W1 = (W1/g)a .......(1)
Net force on heavier block (m2) : W2 - T = (W2/g)a ........(2)
solve eq(1) and (2) find : a = (W2 - W1)/[(W1/g + (W2/g)]
a = ( 75 - 50 ) /( 50/9.8 + 75/9.8 ) = 1.96 m/s2
B) Net force on lighter block ( m1) : F - W1 = (W1/g).a
a = (75 - 50)/(50/9.8) = 4.9 m/s2
accceleration on case b is greater part a because in part a both masses take a part in calculation but in part b only mass of lighter block (m1)take part in calculation