In the Atwood machine shown below, m 1 = 2.00 kg and m 2 = 5.65 kg. The masses o
ID: 2277657 • Letter: I
Question
In the Atwood machine shown below, m1 = 2.00 kg and m2 = 5.65 kg. The masses of the pulley and string are negligible by comparison. The pulley turns without friction and the string does not stretch. The lighter object is released with a sharp push that sets it into motion at vi = 2.15 m/s downward.
magnitude m/s direction ---Select---upwardvelocity is zerodownward In the Atwood machine shown below, m1 = 2.00 kg and m2 = 5.65 kg. The masses of the pulley and string are negligible by comparison. The pulley turns without friction and the string does not stretch. The lighter object is released with a sharp push that sets it into motion at vi = 2.15 m/s downward. How far will m1 descend below its initial level? Find the velocity of m1 after 1.80 s.Explanation / Answer
acceleration of both blocks = [(m2-m1)*g]/(m1+m2)
= 4.67 m/s^2
v^2 - u^2 = 2*a*s
v=0, u=2.15m/s, a=-4.67m/s^2 negative since opposite to velocity
0 - (2.15)^2 = 2*-4.67*s
s = 0.495 m
v= u + a*t
v = 2.15 + (-4.67)*1.8 = -6.256
Direction : upwards