The figure is taken from a paper (Am J Sports Med 2004 32: 477) on injuries to t

Question

The figure is taken from a paper (Am J Sports Med 2004 32: 477) on injuries to the anterior cruciate ligament due to forces applied by the patella tendon. Take a particular case where the attachment force on the tibia is 5870N when the leg is oriented with patella tendon tibial shaft angle of 10° and a knee flexion angle of 13.8°. What is the force on the patella tendon and what are the vertical and horizontal components of the force?

a) What is given in this problem in fundamental units?
Attachment Force: FQ= ?   kg*m.(s*s)

Tibial Shaft Angle:

Knee Flexion Angle:
b) What is the force on the patella tendon?

c) What is the horizontal force on the patella tendon?

d) What is the vertical force on the patella tendon?

Explanation / Answer

a)
fundamental unit for Angle = radian (m*m-1)

Tibial Shaft Angle = 10*/180 = 0.175 radian

Knee Flexion Angle = 13.8*/180 = 0.241 radian

now find Fq,y and Fq,x

given , =13.8, =10

b)

force on petella tendon

Fq = 5870*cos(+) = 5370.81 N

c)

horizontal force on petella tendon

Fq,x = 5870*sin= 1400.19 N

d)

vertical force on petella tendon

Fq,y = 5870*cos = 5700.56 N

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