A horizontal magnetic field of 1.6×10-4 is at an angle of 29 to the direction of

Question

A horizontal magnetic field of 1.6×10-4 is at an angle of 29 to the direction of the current in a straight, horizontal wire 78 long.

If the wire carries a current of 12 , what is the magnitude of the force on the wire?
Express your answer using two significant figures.
=7.3×10-4
Correct


Part B
What angle(s) would be required for the force to be half the value found in part A, assuming nothing else is changed?
Express your answer using three significant figures. If there is more than one answer, enter them in ascending order separated by a comma.
=

Explanation / Answer

IBLsin(29) = (IBLsin)/2

= sin-1[sin(29)/2] = 14.0o, 166o

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