After several large firecrackers have been inserted into it\'s holes (giggity),
ID: 1969995 • Letter: A
Question
After several large firecrackers have been inserted into it's holes (giggity), a bowling ball is projected into the air using a homemade launcher and explodes in midair. During the launch, the 7-kg ball is shot into the air with an initial speed of 10 m/s at a 40o angle; it explodes at the peak of it's trajectory, breaking into three pieces of equal mass. Once piece travels straight up with a speed of 3.0 m/s. Another piece travels straight back with a spee of 2.0 m/s. What is the speed and direction of the third piece?
Please include all formulas used, show all work, and ALWAYS INCLUDE UNITS. This has been a big problem. Thanks so much!
Explanation / Answer
At peak trajectory point velocity is horizontal
vin = 10 cos(40o)
conservation of momentum
mivi = mfvf
mi = 7 kg (intial mass of the ball)
vinitial = 7.66 i m/sec
mf --> 3 pieces of equal mass= mi /3
mf / mi = 3
velocities of
1st piece = 3.0j m/s as travels straight up
2nd piece = travels straight back with a spee of 2.0 = -2i
from equation 3rd piece = 3*7.66 i - 3.0j + 2i = 24.98i - 3j
velocity magnitude is 25.16 m/sec and direction is Tan-1(-3/24.98) = -6.85o