Part A Here on Earth, a simple pendulum of length L is observed to have a freque

Question

Part A Here on Earth, a simple pendulum of length L is observed to have a frequency f. If another pendulum on Earth is observed to have a frequency that is 49f, what is its length?

4802L
L/49
L/4802
L/7
49L
7L
L/2401
2401L

Part B Here on Earth, a simple pendulum of length L is observed to have a frequency f. On another planet a pendulum of length L is observed to have a frequency of 16f. What is the acceleration due to gravity on this planet? In the answers below, g = 9.8 m/s2.

512g
g/256
g/512
g/16
256g
g/4
16g
4g

Explanation / Answer

1/f  = T = 2(l/g) 

a)

l/2401

b)

256g

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