Answer the following What is the change Delta T in the period of a simple pendul

Question

Answer the following What is the change Delta T in the period of a simple pendulum when the acceleration of gravity g changes by Delta g? What is the fractional change in period Delta T/T in terms of the fractional change Delta g/g? Explain how one can use a pendulum to determine the gravitational constant at different elevations using the above result. A pendulum clock, which keeps correct time at a point where g=9.800 m/s2, is found to lose 5.00 s each day at a higher elevation. Use the result of part b to find approximately the value of g at this new location.

Explanation / Answer

T is proportional to 1/g

So This change will lead T = -g/2

(b)

Fractional Change = -1/2

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