Please answer this physics II question, has 3 parts!!! A solenoid is a conductin
ID: 1998016 • Letter: P
Question
Please answer this physics II question, has 3 parts!!!
A solenoid is a conducting coil of wire that is shaped like a helix. By making the solenoid long enough, the field outside the coil is very weak (|vector B| ~ 0). while the field within the coil is approximately uniform. Consider a solenoid of length L. Let n be the turns per unit length---that is. how many tunes the coil of wire winds around over a given distance. Let i_s be the current running through the wire. Find the magnetic field's strength within the solenoid. Test your formula by computing the strength of the magnetic field for each of the three cases given below: Answer box 1: L = 0.40 m. N = 5500 turns, and i_s = 80 mu A Answer box 2: L = 0.10 m, N = 9600 turns, and i_s = 105 mu A Answer box 3: L = 0.30 m. N = 9400 turns, and i_s = 100 mu A Note that in each of the three cases you've been given the total number of turns and will have to compute the number of turns per meter in the solenoid.Explanation / Answer
field inside solenoid, B = u0 n I = u0 (N/L) I
1. B = (4pi x 10^-7) (5500/0.40) (80 x 10^-3 )
B = 1.382 x 10^-3 T
2. B = (4pi x 10^-7) (9600/0.10) (105 x 10^-3 )
B = 0.013 T
3. B = (4pi x 10^-7) (9400/0.30) (100 x 10^-3 )
B = 3.94 x 10^-3 T