Sir Lost-a-Lot dons his armor and sets out from the castle on his trusty steed (

Question

Sir Lost-a-Lot dons his armor and sets out from the castle on his trusty steed (see figure below). Usually, the drawbridge is lowed to a horizontal position so that the end of the bridge rests on the stone ledge. Unfortunately Lost-a-Lot's squire didn't lower the drawbridge far enough and stopped it at = 20.0° above the horizontal. The knight and his horse stop when their combined center of mass is d = 1.00 m from the end of the bridge. The uniform bridge is = 7.50 m long and has a mass of 2 100 kg. The lift cable is attached to the bridge 5.00 m from the hinge at the castle end and to a point on the castle wall h = 12.0 m above the bridge. Lost-a-Lot's mass combined with his armor and steed is 1 050 kg.

(c) Determine the vertical force component acting on the bridge at the hinge.
magnitude

magnitude
You appear to have calculated this force correctly using your incorrect result from part (a). N direction ---Select--- to the left to the right e-meeeeeeee

Explanation / Answer

a) balancing torque about pivot,

T*5 = (1050*9.8*(7.5-1) + 2100*9.8*7.5/2)* cos 20 degree

tension T = (1050*9.8*(7.5-1) + 2100*9.8*7.5/2)* cos 20 degree /5

= 27074 N

b) horizontal force = 27074* sin 20 degree

= 9260 N

c) vertical force = [1050+2100]*9.8 -  27074* cos 20 degree

= 5429 N

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