Part A For the capacitor network shown in the figure, find the equivalent capaci
ID: 1999225 • Letter: P
Question
Part A
For the capacitor network shown in the figure, find the equivalent capacitance.(Figure 1)
Express your answer to two significant figures and include the appropriate units.
Part B
Find the charge on the capacitor a) when the entire combination is connected across a 18 Vbattery.
Express your answer to two significant figures and include the appropriate units.
Part C
Find the charge on the capacitor b) when the entire combination is connected across a 18 Vbattery.
Express your answer to two significant figures and include the appropriate units.
Part D
Find the charge on the capacitor c) when the entire combination is connected across a 18 Vbattery.
Express your answer to two significant figures and include the appropriate units.
Part E
Find the charge on the capacitor d) when the entire combination is connected across a 18 Vbattery.
Express your answer to two significant figures and include the appropriate units.
Explanation / Answer
A) Equivalent capacitance = C = (a+b)II (c+d) =(0.25+0.40)II(0.35+0.5)=0.65*0.85/(0.65+0.85)=0.37F
B) and C) Now charge across first parallel set (0.65 F) is equal to second paralell set(0.85 F) =q (say)
So, q/0.65 + q/ 0.85 =18 ==> q=6.63 C
Now For First Set (0.65 F), voltage across both capacitors will same,but charge divides,
q1/0.25 = q2/0.4 and q1+q2 =6.63
solving these , q1=2.55 C (across capacitor a)
q2 =4.08 C (across capacitor b)
D) and E) Now For second Set (0.85 F), voltage across both capacitors will same,but charge divides,
q3/0.35 = q4/0.5 and q3+q4 =6.63
solving these , q1=2.73 C (across capacitor c)
q4 =3.9 C (across capacitor d)