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A siring connected to a 15.0 kg mass resting on a table passes over a pulley and

ID: 2006067 • Letter: A

Question

A siring connected to a 15.0 kg mass resting on a table passes over a pulley and is connected to a 3.00 kg mass which hangs freely, (see the diagram below) The coefficient of kinetic friction on the horizontal surface is 0.075. Calculate the tension in the string when the 15.0 kg mass is hold stationary. Calculate the acceleration of the masses when they are moving, (magnitude only) Calculate the tension in the string while the masses are moving. A string connected to a 4.00 kg mass resting on a table passes over a frictionless and is connected to a 5.00 kg mass which rests on a surface inclined at an angle of 60.0 degree to the horizontal, (see the diagram below) The coefficient of kinetic friction for the horizontal surface is 0.160 and the coefficient of friction for the inclined surface is 0.120. Calculate the magnitude of the force (the net force) accelerating the system. Calculate the acceleration of the masses when they are moving, (magnitude only) 14) The distance between the sun and the earth is 1.50times1011 m. It takes the earth 3.16times107 seconds to orbit the sun once. Calculate the earth's speed. Calculate the earth's centripetal acceleration (magnitude only).. A satellite is to be positioned so it will pass over Chico twice a day. Calculate the satellite's altitude. Calculate the satellite's speed. Calculate the satellite's centripetal acceleration. Calculate the acceleration due to gravity an the satellite's location. A race track is not banked and has a radius of 316 m. Calculate the state coefficient of friction if the maximum speed at which a race car can travel around the track is 43 m/s (96 mph). A race track has a radius of 316 m and is banked al 15 degree. Calculate the ideal speed for a car traveling around the track.

Explanation / Answer

The radius of track, r = 316 m The speed of car around the track, v = 43 m/s We have a formula from the conservation       Friction force = centrifugal force          mg = mv^2/r        = v^2/rg = 0.597 So the coefficient of friction is = 0.597