In the Bohr model of the hydrogen atom, in the lowest energy state the electron
ID: 2006210 • Letter: I
Question
In the Bohr model of the hydrogen atom, in the lowest energy state the electron orbits the proton at a speed of 2.2 x10^6 m/s in a circular orbit of radius 5.3x10^-11 m.A) What is the orbital period of the electron?
Express your answer using two significant figures.
T =?
B) If the orbiting electron is considered to be a current loop, what is the current I?
Express your answer using two significant figures.
I =?
C) What is the magnetic moment of the atom due to the motion of the electron?
Express your answer using two significant figures.
mu =?
Explanation / Answer
(A) From the definition of speed , speed = distance/tinetime = distance/speed = 2*3.142*5.3*10^-11 /2.2*10^6 m/s
= 15.138 *10^-17 sec = 15.138 *10^-17 sec