I have tried to figure this out a few times, but I keep getting the wrong answer

Question

I have tried to figure this out a few times, but I keep getting the wrong answer. I thought it would simply be the integral for both, but no luck. For (a) I tried At + (1/2)Bt2, At + (1/2)Bt2 + C, and At + (1/2)Bt2N + ?. Not really sure what to do from here. Any help is appreciated.


A shaft is turning at angular speed ? at time t = 0. Thereafter, its angular acceleration is given by
a = A + Bt

(a) Find the angular speed of the shaft at time t. (Use any variable or symbol stated above as necessary.)
?(t) = ?

(b) Through what angle does it turn between t = 0 and t? (Use any variable or symbol stated above as necessary.)
?? = ?

Explanation / Answer

a)the angular speed at t=0s should be given to determine the angular speed at any other time let the angular speed at t=0 is then angular speed at any other instant is integral of (a+bt) from 0 to t + =At+0.5Bt*t+ b)=average speed*time average speed for uniform acceleration is (initial speed+final speed)/2 =+(At+0.5*B*t*t)/2 angle=t+(At*t+0.5Bt*t*t)/2

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