An initially uncharged Air-filled capacitor is connected to a 2.21-V charged sou
ID: 2022917 • Letter: A
Question
An initially uncharged Air-filled capacitor is connected to a 2.21-V charged source. As a result, 7.55*10^-5 C of charge is transferred from one of the capacitor’s plates to the other. Then, while the capacitor remains connected to the charging source, a sheet of dielectric material is inserted between its plates, completely filling the space. The dielectric constant of this sheet is 7.41. Find the capacitor’s potential difference and charge after the insertion
equations I think you need: q=C*V C=(K**A)/d
A) potential difference=?
B) charge=?
Explanation / Answer
given
V0 = 2.21 V
Q = 7.55x10-5 C
K = 7.41
A) find V
V = V0/K
V = 2.21 V / 7.41
V = 0.298 V
B) Q doesn't change
Q = 7.55x10-5 C