Part A-Practice Problem: Constants f an object is placed at a point that is 11.0

Question

Part A-Practice Problem: Constants f an object is placed at a point that is 11.0 cm to the left of a converging lens with focal length of 23 cm , where is the image? Express your answers in centimeters to two significant figures. Lets begin with a relatively simple case of a converging lens that has a focal length of 20 cm. In this example we will see how the image formed by a converging lens can change dramatically as one moves the object closer to the lens. Calculate the image distance and magnification for an object at each of the following distances from the lens: (a) 50 cm, (b) 20 cm, and (c) 15 cm. CTTI Submit Part B-Practice Problem: What is the magnification of the image? Express your answer to two significant figures. Figure

Explanation / Answer

given

do = 11 cm

f = 23 cm

A) di = ?

using lens equation

1/do + 1/di = 1/f

1/di = 1/f - 1/do

1/d = 1/23 - 1/11

di = -21 cm

B) magnification, m = -di/do

= -(-21)/23

= 0.91

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---