Please help me solve for phenotypes/genotypes and punnett square problem! 3) 2 P
ID: 203404 • Letter: P
Question
Please help me solve for phenotypes/genotypes and punnett square problem!
3) 2 POINTS Mrs. Smith and Mrs. Doe were roommates at Harris Hospital and both had daughters at about the same time After Mrs. Smith took Susie home, she became coninced that the babies had been switched. Blood tests were performed with the following results Mr. and Mrs. Smith were both type AB Mr. and Mrs. Doe were both type A Susie Smith was type A Debbie Doe was type O Had a switch occured? Provde an explanation of blood type allele relationships to support your answer 4) 3 POINTS The two diagrams below depict pedigrees of deafness in two different families. For each pedigree provided, the condition of deafness is inherited in which of the following manners? (1) a dominant autosomal characteristic (2) a recessive autosomal characteristic (3) a sex-linked dominant characteristic (4) a sex-linked recessive characteristic Pedigree A Pedigree B afflicted female afflicted male normal female normal male Inheritance Type Inheritance Type Explain your answersExplanation / Answer
3) AB blood group genotype = iAiB
A blood group gneotype= iAi / iAiA
O blood group genotype=ii
Thus blood group of Debbie Doe =ii
whereas Mr.and Mrs. Doe is both A, thus they have the genotype = iAi
for Mr. and Mrs. Smith the blood group is AB=iAiB
thus Susie Smith, when the blood group is A, then the genotype will be =iAiA
Thus we can conclude that no switiching was occured.
4 pedigree A
autosomal dominant mode of inheritance
lets assume the genotype of F1 is Aa for both
Thus, in a cross between Aa X Aa
the children with AA or Aa will show the disease, whereas aa will be normal.
pedigree B
A sex linked-dominant inheritance.
the genotype of the female at F1 might be XaX ( as dominant mode of inheritance, if one X.chromosome is affectted, the the disease will be seen. On the other hand the male is normal, having the genotype XY. They have both the affected and normal childrens.
the genotype of their son and daughter at F2 generation thus will be XaX ( affected daughter), XaY( affected son) and XY (normal son)