Question
Please help me set up this problem from my homeworkassignment. Here is the problem: How many liters of .500M HCl (aq) are needed to reactcompletely with 0.100M of Pb(NO3)2 (aq), forming a precipitate ofPbCl2 (s)? I have the answer but I don't know how to set itup. Thanks, Smee Please help me set up this problem from my homeworkassignment. Here is the problem: How many liters of .500M HCl (aq) are needed to reactcompletely with 0.100M of Pb(NO3)2 (aq), forming a precipitate ofPbCl2 (s)? I have the answer but I don't know how to set itup. Thanks, Smee
Explanation / Answer
2HCl + Pb(NO3)2 -----> PbCl2 + 2HNO3 I think you are not mensioned the Volume of the Pb(NO3)2. Please verified it. EDIT: Thank you for your quick response. The problem Isubmitted is actually part b of a problem. Maybe what you arelooking for is in part a of the problem. Here is part a) Howmany grams of NaOH are needed to neutralize 20.0 ml of 0.015M H2SO4solution? However one doesn't appear to have anything to do withthe other. I gave you all of the information in theproblem. The answer to a) is .240 g The answer to b) is.400 L Thank you. ----------------------------------------------------------------------------------------------------------------- a) How many grams of NaOH are needed to neutralize 20.0 ml of0.015M H2SO4 solution? H2SO4 + 2NaOH ----> Na2SO4 + 2H2O No . of moles of H2SO4 is n = Molarity * Volume inL = 0.015 M * 0.020 L = 0.0003 moles 1 mole of H2SO4 requires 2 moles of NaOH 0.0003 moles of H2SO4 requires 0.0003 * 2 = 0.0006 moles ofNaOH No . of mles n' = mass / Molar mass Molar mass of NaOH M = 23 + 16 + 1 = 40 g / mol So mass of NaOH required m = n' * M = 0.0006 moles * 40 g / mol = 0.024 g Thank you for your quick response. The problem Isubmitted is actually part b of a problem. Maybe what you arelooking for is in part a of the problem. Here is part a) Howmany grams of NaOH are needed to neutralize 20.0 ml of 0.015M H2SO4solution? However one doesn't appear to have anything to do withthe other. I gave you all of the information in theproblem. The answer to a) is .240 g The answer to b) is.400 L Thank you. ----------------------------------------------------------------------------------------------------------------- a) How many grams of NaOH are needed to neutralize 20.0 ml of0.015M H2SO4 solution? H2SO4 + 2NaOH ----> Na2SO4 + 2H2O No . of moles of H2SO4 is n = Molarity * Volume inL = 0.015 M * 0.020 L = 0.0003 moles 1 mole of H2SO4 requires 2 moles of NaOH 0.0003 moles of H2SO4 requires 0.0003 * 2 = 0.0006 moles ofNaOH No . of mles n' = mass / Molar mass Molar mass of NaOH M = 23 + 16 + 1 = 40 g / mol So mass of NaOH required m = n' * M = 0.0006 moles * 40 g / mol = 0.024 g