Please help me out... MasteningPhysics: Ch 22 HW Part 2 Gongle Chram Secure http

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MasteningPhysics: Ch 22 HW Part 2 Gongle Chram Secure https://session.masteringphysics.com/myct/itemView?a assignmentPro ID= 90951 261 &offset;= next Ch 22 HW . Part 2 Problem 22.57 : 90110 >: Constante | Periodic Table Particle 1 carrying charge q is at the origin ol an ry coordinate system. particle 2 carrying charge-2 q is at (10 and partide 3 carrying charge 2 qis at (0 2) Part A What is the angle measured counterclockwise fram the positive r axis of the elactric force axarted on a particla 4 carrying chage q and locatad at (2, 0)? (Hint: Use simple geometry and ratios) Submit ReuestAnswer Provide Feedback Next> O Type here to search 1 ENG 282018

Explanation / Answer

q1 = q

x1 , y1 = 0 , 0

q2 = -2q

x2 , y2 = ( 1, 0 )

q3 = 2q

x3 , y3 = ( 0 , 2)

q4 = q

x4 , y4 = ( 2,0)

force exerted by q1 on q4

F14x = k*q1*q4/r14^2 = k*q*q/2^2 = k*q^4/4

force exerted by q2 on q4

F24x = -k*q2*q4/r24^2 = -k*2q*q/1^2 = -2k*q^2

force exerted by q3 on q4

r34 = sqrt(2^2+2^2) = sqrt8 = 2*sqrt2

F34x = k*q3*q4*cos45/r34^2 = k*2q*q*cos45/8 = k*q^2/(4*sqrt2)

F34y = -k*q3*q4*sin45/r34^2 = -k*2q*q*sin45/8 = -k*q^2/(4*sqrt2)

Fx = F14x + F24x + F34x = -1.573*k*q^2

Fy = F14y + F24y + F34y = 0 + 0 - k*q^2/(4*sqrt2) = -0.177*k*q^2

theta = tan^-1(Fy/Fx) = 186.4<<<<--------------ANSWER

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