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All parts please, Thanks! (50%) Problem 1: Rod AB, which is a conductor of lengt

ID: 2040654 • Letter: A

Question

All parts please, Thanks!

(50%) Problem 1: Rod AB, which is a conductor of length L= 0.15 m and resistance R-180 ?, lies on a horizontal rectangular conducting loop, thus creating two conducting loops, labeled 1 and 2, as in the diagram. The resistance of the rectangular loop is negligible. The setup is located in a uniform, vertically directed magnetic field of strength B-0.45 T, as shown in the diagram. The rod is moving to the right at speed v -0.79 m/s Otheexpertta.com > 20% Part (a) Find the emf, El, in volts, that s induced in loop 1 . Grade Summary Deductions Potential 0% 100% Submissions Attempts remaining: 10 (2% per attempt) detailed view sin) cosO tan cotan0asi acos) atan0acotan) sinh 0 cosh)tanh) cotanh0 Degrees O Radians END BACKSPACE DELCLEAR Submit Hint I give up! Hints: 0% deduction per hint. Hints remaining: 1 Feedback: 0% deduction per feedback. 20% Part (b) What is the direction of the induced current in loop 1 ? 20% Part (c) Find the emf, E2, in volts, that is induced in loop 2 20% Part (d) What is the direction of the induced current in loop 2? 20% Part (e) what is the current, I, in amperes, flowing through the rod?

Explanation / Answer

(A) E1 = B L v  

E1 = 0.45 x 0.15 x 0.79

E1 = 0.0533 Volt

(B) field is into the page and flux is increasing.

so field due to induced current will be out of page.

direction of current -> counter clockwise

(C) E2 = B L v = 0.0533 Volt


(D) flux is decreasing so  

I-> clockwise

(E) E = E1 + E2 = 0.107 Volt

I = E / R = 0.107 / 180

I = 5.925 x 10^-4 A