Particle A of charge 4.00 10-4 C is at the origin, particle B of charge -9.00 10
ID: 2045197 • Letter: P
Question
Particle A of charge 4.00 10-4 C is at the origin, particle B of charge -9.00 10-4 C is at (3.00 m, 0) and particle C of charge 2.00 10-4 C is at (0, 4.00 m).(a) What is the x-component of the electric force exerted by A on C?
.____________ N
(b) What is the y-component of the force exerted by A on C?
_____________.
Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. N
(c) Find the magnitude of the force exerted by B on C.
_______ N
(d) Calculate the x-component of the force exerted by B on C.
________N
(e) Calculate the y-component of the force exerted by B on C.
__________N
(f) Sum the two x-components to obtain the resultant x-component of the electric force acting on C.
_____________N
(g) Repeat part (f) for the y-component.
____________N
(h) Find the magnitude and direction of the resultant electric force acting on C.
magnitude =_________N
direction =____________
° counterclockwise from the +x-axis
Explanation / Answer
Suppose if particle charge 7.00 10-4 C is at the origin, particle B of charge -8.00 10-4 C is at (6.00 m, 0) (a) the x-component of the electric force exerted by A on C is zero N, because the force along Y- axis only. (b) What is the y-component of the force exerted by A onC , Fy = kq1q2/r^2 = 9*10^9*7*10^-4*2*10^-4/16 = 78.75 N (c) the force exerted by B on C, F = -9*10^9*8*10^-4*2*10^-4 /52 F =- 27.692 N the magnitude of the force exerted by B on C is -27.692 N. (d) the x-component of the force exerted by B on C, Fx = F cas? = 27.692cas(33.7)= 23.04 N (e) the y-component of the force exerted by B on C. Fy = F sin? = -15.36 N (f) the sum of x components , Fx = 27.689 N +0 N Fx = 23.04 N (g ) The sum of y components , Fy = 78.75 N -15.36 N Fy = 63.38 N (h) the magnitude F = 67.437 N the direction ? = Fy/Fx = 70 degree