The plates of a parallel plate capacitor each have an area of 0.40m2 and are sep
ID: 2052406 • Letter: T
Question
The plates of a parallel plate capacitor each have an area of 0.40m2 and are separated by a distance of 0.02 m. They are charged until the potential difference between the plates is 3000 V. The charged capacitor is then isolated. Determine the magnitude of the electric field between the capacitor plates. 60 V/m 120 V/m 1.0 times 10 V/m 1.5 times 10 V/m 3.0 times 10 V/m Suppose that a dielectric sheet is inserted to completely fill the space between the plates and the potential difference between the plates drops to 1000 V. Determine the dielectric constant 0.333 0.666 3.0 6.0 2.0 Suppose that a dielectric sheet is inserted to completely fill the space between the plates and the potential difference between the plates drops to 1000 V. What is the capacitance of the system after the dielectric is inserted? 1.8 times 10-10 F 2.7 times 10-10 F 5.4 times 10-10 F 6.2 times 10-10 6.8 times 10-10 FExplanation / Answer
1) E = 3000/.02 = 1.5*10^5 V/m
(d)
2)Q = CV
C1V1 = C2V2
C2/C1 = k = V1/V2 = 3
(c)
3) C = kA/d = 3*8.85*10^-12*0.4/0.02 = 5.4*10^-10
(c)