I only want to see a free body diagram for both blocks... im confused on the in-

Question

I only want to see a free body diagram for both blocks... im confused on the in-between forces. Please show all formulas and step by step how the formulas go together to solve part B. I only dont understand part B

Two blocks are in contact on a frictionless, horizontal tabletop. An external force,
F, is applied to block 1, and the two blocks are moving with a constant acceleration of 2.30 m/s2. Use M1 = 3.17 kg and M2 = 5.50 kg.


(a) What is the magnitude, F, of the applied force?


(b) What is the contact force between the blocks?

(c) What is the net force acting on block 1?
magnitude______________

Explanation / Answer

Total mass = 8.96kg. a) Force = (ma), = 8.96 x 2.5, = 22.4N. b) Contact force = (ma), = 5.85 x 2.5, = 14.625N. c) (22.4 - 14.625) = net 7.775N. Can also be arrived at by (ma) = 3.11 x 2.5, = 7.775N.

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