Part c is the only part I need help with. I just included the other parts just i
ID: 2060864 • Letter: P
Question
Part c is the only part I need help with. I just included the other parts just in case they were necessary for figuring out the answer.
In a proton linear accelerator, a 8.4mA proton current hits a target.
(a)How many protons hit the target each second? N=5.3x10^16 proton/s
(b)How much energy is delivered to the target each second if each proton has a kinetic energy of 28MeV and loses all its energy in the target? U= 2.4x10^5J/s
(c)If the target is a 1.30kg block of copper, at what rate will its temperature increase if it is not cooled?
?T/s=?degrees per second
Explanation / Answer
You may assume that all kinetic energy of the protons will transfer to the heat. So we know that every second 2.4x10^5 J of energy transferred to the bulk of copper. Raise in temperature is given by: delta_T=Q/Cth, when Q is the energy transferred and Cth - is the thermal mass . Thermal mass is Cth=m*c, when c is the specific heat capacity. In case of copper c=0.38 J/(C*g) so Cth=0.38*1300=494 J/C Then Delta_T=2.4x10^5/494=485.8 deg so the rate will be 485.8 deg/sec