Part c and d? http//wwwwwwebassign netweb/student/Assignment Resp Eat vew Favori

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Part c and d? http//wwwwwwebassign netweb/student/Assignment Resp Eat vew Favorites Tool Help 2030 points l Previoun Answers sorpsra 25Poes Two parallel plates having charges of equal magnitude but opposte sign are separated by 17 o em Each plate has a surface charge density of 30 o noym?. A proton is released from rest at the positive plate. (a) Determine the potential drference between the plates, (b) Determine the kinetic energy of the proton when it reaches the negative plate. 92e-17 (c) Determine the speed of the proton just before it strikes the negative plate Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation, Carry out all intermediate results to at least four-digit accuracy to minimize roundoff en or, km/s td) Determine the acceleration of the proton. Your response is within 10% of the conrect value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four digit accuracy to minimize roundorf error, m/s (towards the negative plate) Determine the force on the proton 542e 16 N (towards the negative plate. (y From the force, snd the magnitude of the electric field. show that it is equal to that electric field found from the charge densities on the plates. (Do this an paper. Your instructor may ask you to turn in this work) Need Help?

Explanation / Answer

C) speed of the proton is v = ?

but from B) KE = 0.5*m*v^2 = 9.2*10^-17

v = sqrt(2*9.2*10^-17/(1.67*10^-27)) = 3.32*10^5 m/s

D) Force F = q*E

E = sigma/eo = 30*10^-9/(8.85*10^-12) = 3389.83 N/C

F= 1.6*10^-19*3389.83 = 5.423*10^-16 N

m*a = 5.423*10^-16

accelaration a = 5.423*10^-16/(1.67*10^-27) = 3.24*10^11 m/s^2

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