Here is the answer to this problem. Can you explain how to work out the trihybri
ID: 206944 • Letter: H
Question
Here is the answer to this problem. Can you explain how to work out the trihybrid cross and how to find out which genotypes are recombinant to get these answers in the chart? I'm very confused.
16) Trihybrid Cross You are working in a genetics lab using Drosophila melanogaster studying the following three alleles: k (kidney-shaped eyes instead of wild-type round), c (cardinal-colored eyes instead of wild-type red), and e (ebony body instead of wild-type gray). All three of these genes hypothesized to be part of the same linkage group. Females with kidney-shaped, cardinal-colored eyes were mated with ebony males. The Fi was wild type +) for all three traits. When Fi females were testcrossed with k/k.c/c.e/e males, the following offspring phenotypes were obtained. k ce: 3; k c +: 876; k + e: 67; k + +: 49: + ce: 44; +c+: 58:++ e: 899; +++:4 Note that there is a1 to 1 correspondence between the F2's phenotypes and the haplotype they inherited from their dihybrid Fi parent. Thus, in the table below we simply refer to the offspring by the haplotype they received from the Fi parent. Additionally, since it is not clear whether the genes are linked or not, their order in the data does not necessarily reflect their order on a chromosome Arrange your data below starting with the most frequent gamete genotype produced by the trihybrid and ending with the least frequent genotype. F1 Gamete Genotype Observed k andc c ande k and e Recombinant for loci 876 67 58 49 kc+ kt e + ce kce Counts 2000 218 100 132Explanation / Answer
Female genotype: k c +
male genotype : + + e
F1 is wild type for all characters so genotype will be : + + +
when test crossed with k c e
offsprings obtained were
k c e= 3 (least frequent) recombinants
+ + + = 4 recombinants
+ c e= 44 recombinants
k + += 49 recombinants
+ c += 58 recombinants
k + e= 67 recombinants
k c += 876 parental
+ + e= 899 (most frequent) parental